Question

=(M6+M7+M8+M9+M10+M11+M12)/7

Answer 1

Respuesta:

1/7 (M^6 + M^7 + M^8 + M^9 + M^10 + M^11 + M^12)

1/7 M^6 (M^6 + M^5 + M^4 + M^3 + M^2 + M + 1)

-1/7 ((-1)^(2/7) - M) ((-1)^(4/7) - M) (-M + (-1)^(5/7) - (-1)^(4/7) + (-1)^(3/7) - (-1)^(2/7) + (-1)^(1/7) -

1) M^6 (M + (-1)^(1/7)) (M + (-1)^(3/7)) (M + (-1)^(5/7))

M^12/7 + M^11/7 + M^10/7 + M^9/7 + M^8/7 + M^7/7 + M^6/7

M = 0