Question

Me pueden ayudar porfavor:( es para hoy es de logaritmo

Answer 1

Explicación paso a paso:

• $log(2x {}^{2} + 1) = log(x + 1) {}^{2}$
• ${2x}^{2} + 1 = (x + 1) {}^{2}$
• $2x {}^{2} + 1 = {x}^{2} + 2x + 1$
• ${2x}^{2} = {x}^{2} + {2x}^{}$
• ${2x}^{2} - {x}^{2} - 2x = 0$
• ${x}^{2} - 2x = 0$
• $x(x - 2) = 0$
• $x = 0.2$
• $x = 2$