Question

$\frac{2}{3} + \sqrt[3] \frac{125}{27} \div \frac{2}{2} + \sqrt[4] \frac{64}{81} - \sqrt[5] \frac{1}{243} \div \frac{3}{3} =$
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Answer 1

Explicación paso a paso:

$\frac{2}{3} + \sqrt[3]{ \frac{125}{27} } \div \frac{2}{2} + \sqrt[4]{ \frac{64}{81} } - \sqrt[5]{ \frac{1}{243} } - \frac{3}{3} \\ \frac{2}{3} + \frac{ \sqrt[3]{125} }{ \sqrt[3]{27} } \div 1 + \frac{ \sqrt[4]{64} }{ \sqrt[4]{81} } - \frac{ \sqrt[5]{1} }{ \sqrt[5]{243} } - 1 \\ \frac{2}{3} + \frac{5}{3} \div 1 + \frac{ \frac{141}{50} }{3} - \frac{1}{3} - 1 \\ \frac{2}{3} + \frac{ \frac{5}{3} }{1} + \frac{ \frac{141}{50} }{3} - \frac{1}{3} - 1 \\ \frac{2}{3} + \frac{5}{3} + \frac{141}{50(3)} - \frac{1}{3} - 1 \\ \frac{2}{3} + \frac{5}{3} + \frac{141}{150} - \frac{1}{3} - 1 \\ \frac{2 + 5}{3} + \frac{141}{150} - \frac{1}{3} - 1 \\ \frac{7}{3} + \frac{141}{150} - \frac{1}{3} - 1 \\ \frac{1050 + 423}{450} - \frac{1}{3} - 1 \\ \frac{1473}{450} - \frac{1}{3} - 1 \\ \frac{491}{150} - \frac{1}{3} - 1 \\ \frac{1473 - 150}{450} - 1 \\ \frac{1323}{450} - 1 \\ \frac{147}{50} - 1 \\ \frac{147 - 50}{50} \\ \frac{97}{50} = 1.94$