Question

Siendo tg5x ctg(24º + x) = 1, Calcula: L = sen5x + cos2(7x+3º)​

Answer 1

Respuesta:

1/2

Explicación paso a paso:

tg5x ctg(24 + x) = 1

5x = 24 + x

4x = 24

x = 6

L = sen5x + cos2(7x+3)​

L = sen30 + cos2(45)​

L= sen30 + cos90

L= 1/2+ 0

L = 1/2