Question

ayuda...usando la formula general :3
$5x ^2 + 7 \times + 2 = 0$
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Answer 1

Respuesta:

        $x= \frac{-2}{5}$       ;         $x = -1$

Explicación paso a paso:

$5x^{2} +7x+2=0$

Aplicando la fórmula general.

$a=5;b=7;c=2$

$x = \frac{-b\frac{+}{}\sqrt{b^{2} -4ac} }{2a} = \frac{-7\frac{+}{}\sqrt{7^{2}-4(5)(2) } }{2(5)}$

$x = \frac{-7\frac{+}{}\sqrt{49-40} }{10} = \frac{-7\frac{+}{} \sqrt{9} }{10}= \frac{-7\frac{+}{}3 }{10}$

$x = \frac{-7+3}{10} = \frac{-4}{10} =\frac{-2}{5}$

$x = \frac{-7-3}{10} = \frac{-10}{10} = -1$

Solución:

$x =\frac{-2}{5} ; x = -1$