Question

Alguien me ayuda a resolver estas dos ecuaciones cuadráticas​

Answer 1

Explicación paso a paso:

$1.(x - 6)(x - 3) = 4 \\ {x}^{2} - 9x + 18 = 4 \\ x {}^{2} - 9x + 14 = 0 \\ (x - 2)(x - 7) = 0 \\ x - 2 = 0 \\ x = 2 \\ x - 7 = 0 \\ x = 7 \\ 2.(x + 5)(x - 2) = 8 \\ x {}^{2} + 3x - 10 = 8 \\ x {}^{2} + 3x - 18 = 0 \\ (x - 3)( x + 6) = 0 \\ x - 3 = 0 \\ x = 3 \\ x + 6 = 0 \\ x = - 6$