Question

determina la composición porcentual de HCOOCH2 CH3

Answer 1

HCOOCH2CH3

MASA MOLECULAR:

H: 6 x 1 = 6 g/mol
C: 3 X 12 = 36 g/mol
O: 2 x 16 = 32 g/mol
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       Mm = 74 g/mol

HIDROGENO
 74 g --- 100 %
   6 g ----  x
   x = 8.10 %

carbono:
74 g --- 100 %
36 g ----  x
  x = 48,64 %

OXIGENO
74 g --- 100 %
32 g --- x
  x = 43.2 %