Question

ayuda plis contéstenme doy corona y estrellas

Answer 1

Hola!

Respuesta:

$m \angle AOB = 3k = 3(16°) = 48°$

Explicación paso a paso:

∆ Solución:

$2(m \angle AOB) = 3(m \angle BOC) \\ \\ \frac{2}{3} = \frac{m \angle BOC}{m \angle AOB} \\ \\\frac{2k}{3k} = \frac{m \angle BOC}{m \angle AOB} \\ \\ m \angle BOC = 2k \\ m \angle AOB = 3k \\ \\ \\ m \angle AOC = 80° \\ m \angle AOC =m \angle AOB + m \angle BOC\ \\ 80° = m \angle AOB + m \angle BOC \\ 80° = 3k + 2k \\ 80° = 5k \\ 16° =k \\ \\ ∴ \\ m \angle BOC = 2k = 2(16°) =32° \\ m \angle AOB = 3k = 3(16°) = 48°$