Question

hallar b ... ............​

Answer 1

Respuesta:

               $18$

Explicación paso a paso:

$Por-el-teorema -de-las-altuas:$

$(Altuta)^{2} = (48) (BC-48) = (48)(54-48) = 48(6)$

$(altura)^{2} = (288)$

$altura = \sqrt{288} = \sqrt{144*2} = 12\sqrt{2}$

$Altura= 12\sqrt{2}$

$Por-el -teorema-de-Pitagoras:$

$b^{2} = (Altura)^{2} + ( BC-48)^{2}$

$b^{2} = (12\sqrt{2} )^{2} + (54-48)^{2} = (12)^{2} *\sqrt{4} + 6^{2} = 288+36$

$b^{2} =324$

$b = \sqrt{324}$

$b = 18$