Question

Factoriza
3ab(a+b)+3(a+b)²c+3(a+b)c²

Answer 1

Respuesta:

$3a^2b+3ab^2+3a^2c+6abc+3b^2c+3ac^2+3bc^2$

Explicación paso a paso:

$3ab\left(a+b\right)+3\left(a+b\right)^2c+3\left(a+b\right)c^2\\\\=3ab\left(a+b\right)+3c\left(a+b\right)^2+3c^2\left(a+b\right)\\\\=3a^2b+3ab^2+3c\left(a+b\right)^2+3c^2\left(a+b\right)\\\\=3a^2b+3ab^2+3a^2c+6abc+3b^2c+3c^2\left(a+b\right)\\\\=3a^2b+3ab^2+3a^2c+6abc+3b^2c+3ac^2+3bc^2$