Question

Es súper urgente este tema es de problemas de aplicación del teorema de Pitágoras

Answer 1

Explicación paso a paso:

$1...... \\ {13}^{2} = {x}^{2} + {12}^{2} \\ x = \sqrt{ {13}^{2} - {12}^{2} }$

$2..... \\ {15}^{2} = {12}^{2} + {x}^{2} \\ x = \sqrt{ {15}^{2} - {12}^{2} }$

$3..... \\ {x}^{2} = {8}^{2} + {15}^{2} \\ x = \sqrt{ {8}^{2} + {15}^{2} }$

${x}^{2} = {24}^{2} + {18}^{2} \\ x = \sqrt{ {24}^{2} + {18}^{2} }$

${x}^{2} = {3}^{2} + {4}^{2} \\ x = \sqrt{9 + 16} = \\ x = \sqrt{25} = 5$