Question

X2+Y2+Z2=4 ecuación lineal

Answer 1

Respuesta:

$x=2-y-z$

Explicación paso a paso:

$x\cdot \:2+y\cdot \:2+z\cdot \:2=4\\\\x\cdot \:2+y\cdot \:2+z\cdot \:2-\left(y\cdot \:2+z\cdot \:2\right)=4-\left(y\cdot \:2+z\cdot \:2\right)\\\\x\cdot \:2=4-2y-2z\\\\\frac{x\cdot \:2}{2}=\frac{4}{2}-\frac{2y}{2}-\frac{2z}{2}\\\\\frac{x\cdot \:2}{2}\\\\=x\\\\\frac{4}{2}-\frac{2y}{2}-\frac{2z}{2}\\\\=\frac{4-2y-2z}{2}\\\\4-2y-2z\\\\=2\cdot \:2-2y-2z\\\\=\frac{2\left(2-y-z\right)}{2}\\\\x=2-y-z$