Question

OPERACIONES COMBINADAS DE NÚMEROS RACIONALES (Q).​

Answer 1

Respuesta:

Está correcto....

Explicación paso a paso:

$\sqrt[3]{(\frac{3}{2})^{9}} \\\\=\sqrt[3]{\frac{3^{9} }{2^{9}}}\\\\=\sqrt[3]{\frac{19.683}{2^{9}}}\\\\=\sqrt[3]{\frac{19.683}{512}}\\\\=\frac{\sqrt[3]{19.683}}{\sqrt[3]{512}} \\\\=\frac{\sqrt[3]{19.683}}{8}} \\\\=\frac{2,7}{8}$

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$\frac{11}{2} -3(\sqrt[3]{\frac{30 - 3}{8} }) \\\\= \frac{11}{2} -3(\sqrt[3]{\frac{27}{8} })\\\\= \frac{11}{2} -3(\frac{\sqrt[3]{27} }{\sqrt[3]{8} })\\\\= \frac{11}{2} -3(\frac{3}{\sqrt[3]{8} })\\\\=\frac{11}{2} -3(\frac{3}{2})\\\\=\frac{11}{2} -\frac{3(3)}{2}\\\\=\frac{11}{2} -\frac{9}{2}\\\\=\frac{11 - 9}{2} \\\\=\frac{2}{2} \\\\= 1$

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$\frac{7}{2} -12(\frac{4}{3} +\sqrt{\frac{4}{9}} )^{2}\\\\=\frac{7}{2} -12(\frac{4}{3} +\frac{\sqrt{4}}{\sqrt{9}} )^{2}\\\\=\frac{7}{2} -12(\frac{4}{3} +\frac{2}{\sqrt{9}} )^{2}\\\\=\frac{7}{2} -12(\frac{4}{3} +\frac{2}{3} )^{2}\\\\=\frac{7}{2} -12(\frac{4 + 2}{3} )^{2}\\\\=\frac{7}{2} -12(\frac{6}{3} )^{2}\\\\=\frac{7}{2} -12(2)^{2}\\\\=\frac{7}{2} -12(4)\\\\=\frac{7}{2} -48\\\\=\frac{7}{2} +\frac{-96}{2}\\\\=\frac{7 - 96}{2} \\\\=-\frac{89}{2}$