Question

3x5+3-2x7+1 me tiene que dar 8, 23,128,11 y 9 encerrandolo en paréntesis

Answer 1

sol
3x5+3-2x7+1 = (3x(5+3))-(2x(7+1)) = (3x8) -( 2x8) = 24-16 = 8
3x5+3-2x7+1= (3x5)+(3-2)x(7+1) = 15 +1x8 = 15+8 =23
3x5+3-2x7+1=((3x5)+(3-2))x(7+1) = (15 +1)x(8) = 16*8 =128
3x5+3-2x7+1=(3x(5+3))-(2x7)+1=(3x8)-14+1=24-14+1 =10+1 =11
3x5+3-2x7+1=(3x(5+3))-((2x7)+1) = (3x8) - (14+1) =24-15= 9