Question

PORRR FAVOOOOOORRRRRRR PARA AHORA PLIS :C

Answer 1

☆ RESOLUCIÓN:

$\boxed{AB = x}$

$\boxed{BC = y}$

$\boxed{AC = z}$

$\boxed{AC = AB + BC}$

$AC + AB = \frac{4}{3} (BC) \\ AB + BC + AB = \frac{4}{3} (BC) \\ 2AB + BC = \frac{4}{3} (BC) \\ 2AB = \frac{4}{3} (BC) - BC \\ 2AB = \frac{1}{3} (BC) \\ 2AB \times 3 = BC \\ 6AB = BC \\ \boxed{\frac{AB}{BC} = \frac{1}{6} }$

∴ RESPUESTA:

$\boxed{ \frac{AB}{BC} = \frac{1}{6} }$