Question

por ayuda es urgente​

Answer 1

$\acute Area_{\overline{A'MA}}=\frac{\overline{A'M}\cdot\overline{MA}\cdot\overline{AA'}}{4r}\\\\\acute Area_{\overline{A'MA}}=\frac{crd(90\°-\theta)r\cdot crd(90\°+\theta)r\cdot2r}{4r}\\\\\acute Area_{\overline{A'MA}}=\frac{2sen(\frac{90\°-\theta}{2})\cdot 2sen(\frac{90\°+\theta}{2})\cdot r\²}{2}\\\\\acute Area_{\overline{A'MA}}=(2cos\²(\frac{\theta}{2})-1)\cdot r\²$