Question

3 (2x-6) - [(x - (3x-8) + 2) - 1] = 2-(3-2x)
alguien me ayuda porfavor
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Answer 1

Respuesta:

3(2x-6) - [(x - (3x-8) + 2) - 1] = 2-(3-2x)

6x - 18 - [(x - 3x + 8 + 2) - 1] = 2 - 3 + 2x

6x - 18 -[(-2x + 10) - 1] = -1 + 2x

6x - 18 - [-2x + 9] = -1 + 2x

6x - 18 + 2x - 9 = -1 + 2x

6x + 2x - 2x = -1 + 18 + 9

6x = 26

x = 26/6

x = 13/3

Explicación paso a paso: