Question

quien me ayuda con esto​

Answer 1

EJERCICO 4

$\frac{-10}{3}+\frac{4}{5}-\frac{9}{15}+\frac{1}{3}-\frac{12}{5}$

$\mathrm{Aplicar\:las\:propiedades\:de\:las\:fracciones}:\quad \frac{-a}{b}=-\frac{a}{b}\\\\=-\frac{10}{3}+\frac{4}{5}-\frac{9}{15}+\frac{1}{3}-\frac{12}{5}\\\\=\frac{-9}{3}+\frac{4}{5}-\frac{9}{15}-\frac{12}{5}\\\\=\frac{-9}{3}+\frac{-8}{5}-\frac{9}{15}\\\\=\frac{-9}{3}+\frac{-8}{5}-\frac{3}{5}\\\\=\frac{-9}{3}+\frac{-11}{5}\\\\=\frac{-45}{15}+\frac{-33}{15}\\\\=\frac{-45-33}{15}\\\\=\frac{-78}{15}\\\\=-\frac{26}{5}$

EJERCICIO 5

$\frac{2}{5}\cdot \frac{7}{3}\cdot \frac{9}{5}\\\\=\frac{2\cdot \:7\cdot \:9}{5\cdot \:3\cdot \:5}\\\\=\frac{2\cdot \:7\cdot \:9}{5^2\cdot \:3}\\\\=\frac{2\cdot \:7\cdot \:3\cdot \:3}{5^2\cdot \:3}\\\\=\frac{2\cdot \:7\cdot \:3}{5^2}\\\\=\frac{42}{5^2}\\\\=\frac{42}{25}$