Question

1) (3a + 2b + c)²

2) ((3x²+y)³

3) (2a⁵ + 3b)

Answer 1

Respuesta:

1) (3a + 2b + c)²

$\left(3a+2b+c\right)^2\\\\=\left(3a+2b+c\right)\left(3a+2b+c\right)\\\\=12ab+6ac+9a^2+4b^2+4bc+c^2$

2) ((3x²+y)³

$\left(3x^2+y\right)^3\\\\=\left(3x^2\right)^3+3\left(3x^2\right)^2y+3\cdot \:3x^2y^2+y^3\\\\=27x^6+27x^4y+9x^2y^2+y^3$

3) (2a⁵ + 3b)

$=2a^5+3b$