Question

Funciones...........

Answer 1

f(x) = 3X + 2;  g(x) = (X + 3)/(2X + 1)

g o f = g[f(x)]

g[f(x)] = [(3X + 2) + 3]/[2(3X + 2) + 1]

g[f(x)] = [3X + 5]/[6X + 4 + 1]

g[f(x)] = [3X + 5]/[6X + 5]

f o g: f[g(x)]

f[g(x)] = 3[(X + 3)/(2X + 1)] + 2

3[(X + 3)/(2X + 1)] = [(3X + 9)/(2X + 1)] + 2

[(3X + 9)/(2X + 1)]  + 2/1 = [(3X + 9) + 2(2X + 1)]/[2X + 1]

[(3X + 9) + (4X + 2)]/[2X + 1]

[3X + 9 + 4X + 2]/[2X + 1]

[7X + 11]/[2X + 1]

f[g(x)] = [7X + 11]/[2X + 1]
 
 

Answer 2

Respuesta:

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Explicación paso a paso: