Question

log x^2 - log (x + 1)^2 = 0
Por favor!

Answer 1

$Log x^2 - log (x + 1)^2 = 0 \\ \\ aplicamos \ propiedad \\ \\ Log \dfrac{x^2}{(x+1)^2}=0 \qquad \qquad Resolvemos \quad log_aB=c\to a^c=B \\ \\ \\ 10^0= \dfrac{x^2}{(x+1)^2} \\ \\ \\ 1= \dfrac{x^2}{(x+1)^2} \\ \\ (x+1)^2= x^2 \\ \\ x^2+2x+1=x^2 \\ \\ x^2-x^2+2x= -1 \\ \\ 2x=-1\quad \to \boxed{x= -\frac{1}{2} }$

Espero que te sirva, salu2!!!!