Question

1)Sea la función P(x) = 4x2 + 5x + 6 : Calcular P(y + 1) NO ENTIENDO ​

Answer 1

Explicación paso a paso:

$p(x) = 4 {x}^{2} + 5x + 6$

$p(y + 1) = 4( {y + 1)}^{2} + 5(y + 1) + 6 \\ p(y + 1) = 4( {y}^{2} + 2y + 1) + 5y + 5 + 6 \\p(y + 1) = 4 {y}^{2} + 8y + 4 + 5y + 5 + 6 \\p(y + 1) = 4 {y }^{2} + 8y + 5y + 15 \\ p(y + 1) = 4 {y}^{2} + 13y + 15$