Question

ayúdame plis
√25x9 - ∛(√(4^12 ))

∜(√(3^24 )) - ∛(-64)

∛8x125- √(6^4 )

Answer 1

━━━━━━━━✦✗✦━━━━━━━━

$\sqrt{25\cdot \:9}-\sqrt[3]{\sqrt{4^{12}}}\\\\15-4^{2} \\\\-1$

$\sqrt[4]{\sqrt{3^{24}}}-\sqrt[3]{-64}$

$3^{3} - (-4)\\27 + 4\\31$

$\sqrt[3]{8\cdot \:125}-\sqrt{6^4}\\\\=10-6^2\\\\=10-36\\\\=-26$

━━━━━━━━✦✗✦━━━━━━━━

Suerte