Question

con resolución porfavor alluda ​

Answer 1

☆ RESOLUCIÓN:

A I.P B

$6 \times (a + 1) = (a - 1) \times 8 = {k}^{2} \times 12$

$6 \times (a + 1) = (a - 1) \times 8 \\ 6a + 6 = 8a - 8 \\ 6 + 8 = 8a - 6a \\ 14 = 2a \\ \frac{14}{2} = a \\  \boxed{7 = a}$

$6 \times (a + 1) = {k}^{2} \times 12 \\ 6 \times (7 + 1) = {k}^{2} \times 12 \\ 6 \times 8 = {k}^{2} \times 12 \\ 48 = {k}^{2} \times 12 \\ \frac{48}{12} = {k}^{2} \\ 4 = {k}^{2} \\ \sqrt{4} = k \\  \boxed{2 = k}$

☆ RESPUESTA:

$\boxed{k = 2}$