Question

En la figura ABCD es un cuadrado, cuyo perímetro mide 80cm. Calcula el área de la región sombrada.

Answer 1

Respuesta:

$A = \frac{(B+b)h}{2} = \frac{(20cm+10cm)(10cm)}{2} = \frac{(30cm)(10cm)}{2} =\frac{300cm^{2} }{2} =150cm^{2}$

Explicación paso a paso:

P = 80cm

P = 4L

80 =4L

L = 80/4

L = 20cm

La figura sombreada es un trapecio

h = L/2 = 20/2= 10cm

b = 10cm

B = 20cm

$A = \frac{(B+b)h}{2} = \frac{(20cm+10cm)(10cm)}{2} = \frac{(30cm)(10cm)}{2} =\frac{300cm^{2} }{2} =150cm^{2}$

Answer 2

P = 80cm

P = 4L

80 =4L

L = 80/4

L = 20cm

La figura sombreada es un trapecio

h = L/2 = 20/2= 10cm

b = 10cm

B = 20cm

A = \frac{(B+b)h}{2} = \frac{(20cm+10cm)(10cm)}{2} = \frac{(30cm)(10cm)}{2} =\frac{300cm^{2} }{2} =150cm^{2}A=2(B+b)h=2(20cm+10cm)(10cm)=2(30cm)(10cm)=2300cm2=150cm2