Question

holaaa
me ayudan porfa urgente doy corona si está bien la respuesta
con su comprobación y operación porfa:

1. 2(2x-3) = 6+ X


2. 4(X-10) = -6(2-X) -6X


3. 2(x+1)-3( X-2) = X+6​

Answer 1

Respuesta y Explicación paso a paso:

1. 2(2x - 3) = 6 + x:

2(2x - 3) = 6 + x

4x - 6 = 6 + x

4x - x = 6 + 6

3x = 12

x = 12/3

x = 4

Comprobación:

2(2(4) - 3) = 6 + 4

2(8 - 3) = 6 + 4

16 - 6 = 6 + 4

10 = 10

2. 4(x - 10) = -6(2 - x) - 6x:

4(x - 10) = -6(2 - x) - 6x

4x - 40 = -6(2 - x) - 6x

4x - 40 = -12 + 6x - 6x

4x - 40 = -12

4x = -12 + 40

4x = 28

x = 28/4

x = 7

Comprobación:

4(7 - 10) = -6(2 - 7) - 6(7)

28 - 40 = -6(2 - 7) - 6(7)

-12 = -6(2 - 7) - 6(7)

-12 = -12 + 42 - 42

-12 = 30 - 42

-12 = -12

3. 2(x + 1) -3(x - 2) = x + 6:

2(x + 1) -3(x - 2) = x + 6

2x + 2 -3(x - 2) = x + 6

2x + 2 -3x + 6 = x + 6

2x - 3x + 2 + 6 = x + 6

-x + 2 + 6 = x + 6

-x + 8 = x + 6

-x - x = 6 - 8

-2x = -2

x = -2/-2

x = 1

Comprobación:

2(1 + 1) -3(1 - 2) = 1 + 6

2 + 2 -3(1 - 2) = 1 + 6

2 + 2 - 3 + 6 = 1 + 6

4 - 3 + 6 = 1 + 6

1 + 6 = 1 + 6

7 = 7

4. $\frac{x - 6}{6} -\frac{x-3}{2} =1$:

$\frac{x - 6}{6} -\frac{x-3}{2} =1$

$\frac{x - 6}{6} *6-\frac{x-3}{2}*6 =1*6$

x - 6 - 3(x - 3) = 6

x - 6 - 3x + 9 = 6

x - 3x - 6 + 9 = 6

-2x - 6 + 9 = 6

-2x + 3 = 6

-2x = 6 - 3

-2x = 3

x = $-\frac{3}{2}$

Comprobación:

$\frac{-\frac{3}{2}-6 }{6}-\frac{-\frac{3}{2}-3 }{2}=1$

$-\frac{5}{4} -\frac{-\frac{3}{2}-3 }{2}=1$

$-\frac{5}{4} -\frac{9}{4}=1$

1 = 1

5. $\frac{3}{2} (2x+4)=x+20$:

$\frac{3}{2} (2x+4)=x+20$

3x + 6 = x + 20

3x - x = 20 - 6

2x = 14

x = 14/2

x = 7

Comprobación:

$\frac{3}{2} (2(7)+4)=7+20$

$\frac{3}{2} (14+4)=7+20$

21 + 6 = 7 + 20

27 = 27

6. $\frac{4}{x-3} =\frac{5}{x-2}$:

$\frac{4}{x-3} =\frac{5}{x-2}$

4(x - 2) = 5(x - 3)

4x - 8 = 5x - 15

4x - 5x = -15 + 8

-x = -7

x = -7/-1

x = 7

Comprobación:

$\frac{4}{7-3} =\frac{5}{7-2}$

$\frac{4}{4} =\frac{5}{5}$

1 = 1