Question

Si: P(x) = x² + x+ 5 Q(x) = 5x² + 2x - 3 R(x) = -3x³ - 4x + 1 calcular: 2P(x) + Q(x) + R(x)​

Answer 1

Solucion:

P(x) = x² + x + 5

Q(x) = 5x² + 2x - 3

R(x) = -3x³ - 4x + 1

Calcular: 2P(x) + Q(x) + R(x)​

= 2(x² + x + 5) + (5x² + 2x - 3 ) + (-3x³ - 4x + 1 )

= 2x² + 2x + 10 + 5x² + 2x - 3 - 3x³ - 4x + 1

Ordenamos para facilitar la suma:

= 2x² + 2x + 10 + 5x² + 2x - 3 - 3x³ - 4x + 1

= -3x³ + (2x² + 5x²) + (x + 2x - 4x) + (10 - 3 + 1)

= -3x³ + 7x² - x + 8

Espero te haya ayudado:)