Question

{[6-2-3x(-2+2x)]}=[2x-(3x-2x)]​

Answer 1

Respuesta:

[6-2-3x(-2+2x)] = [2x-(3x-2x)]​

[ 6-2+6x-6x^2 ] = [ 2x-3x+2x ]

[ 4 + 6x -6x^2 ] = [ 4x-3x ]

4+6x-6x^2 = 4x-3x

4+6x-6x^2 = x

-6x^2+6x+4 = x

-6x^2+6x+4-x = x-x

-6x^2+(6-1)x+4 = 0

-6x^2+5x+4 = 0

-(-6x^2+5x+4) = -(0)

6x^2-5x-4 = 0

Factorización :

6x^2-5x-4 = 0

6x^2-8x+3x-4 = 0

2x(3x-4)+(3x-4) = 0

(3x-4)(2x+1) = 0

Obtengo los valores de X :

X1 = 4/3 y X2 = -1/2

Explicación paso a paso: