Question

♡︎
ES DE CURSO QUÍMICA PORFAVOR

Answer 1

Respuesta:

CaO: 40g + 16g = 56 g/mol

Fe2O3 = 2(56)g + (16 x3)g = 160 g/mol

Al(OH)3 = 27 g + (3x 16)g + (3 x 1)g = 78 g/mol

Explicación:

CaO: 40g + 16g = 56 g/mol

Fe2O3 = 2(56)g + (16 x3)g =  160 g/mol

Al(OH)3 = 27 g + (3x 16)g + (3 x 1)g =  78 g/mol

Na2O = (2 x 23)g + 16 g = 62 g/mol

PH3 = 31 g + (3 x 1)g = 34 g/mol

CaCO3 = 40 + 12 g + 48 g = 100 g/mol

H2SO4 = ( 2 x 1)g + 32 g + 64 g = 98 g/mol

Fe2(CO3)3 = (2 x 56)g + (3 x 12)g + (9 x 16)g = 292 g/mol

C6H12O6 = ( 6 x 12)g + (12 x 1)g + (6 x 16)g = 180 g/mol

Na2SO4 = (2 x 23)g + 32 g + (4 x 16)g = 142 g/mol