Question

AYUDA!!!
tengo que sacar el peso molecular de estos compuestos:

-Al2 SO3

-K2O

-Na2o

-CaSO4

-PbCl2

-Li2O

-NaOH

-FeO

-Fe2O3

-Mn2O7

-Hg2O

-Al2O3

-V2O5

-MgO

-CuO

-PlO2

-OCdO

PORFAVOR!!!!

Answer 1

Al2 (SO3)3
Al: 2 x 27 = 54 g/mol
S: 3 x 32 = 96 g/mol
O: 9 x 16 = 144 g/mol
````````````````````````````
         Mm = 297 g/mol

-K2O
K: 2 x 39 =78 g/mol
O: 1 x 16 = 16 g/mol
``````````````````````````
     Mm = 94 g/mol
 
-Na2O
Na: 2 x 23 = 46 g/mol
 O: 1 x 16 = 16 g/mol
````````````````````````````````
           Mm = 62 g/mol

-CaSO4
Ca: 1 x 40 = 40 g/mol
 S: 1 x 32 = 32 g/mol
 O: 4 x 16 = 64 g/mol
``````````````````````````````
         Mm = 136 g/mol

-PbCl2
Pb: 1 x 207 = 207 g/mol
Cl: 2 x  35.45 = 70.9 g/mol
````````````````````````````````````
           Mm = 277.9 g/mol

-Li2O
Li: 2 x 7 = 14 g/mol
 O: 1 x 16 = 16 g/mol
````````````````````````````
         Mm = 30 g/mol

-  NaOH
Na: 1 x 23 = 23 g/mol
 O: 1 x 16 = 16 g/mol
 H: 1 x 1 = 1 g/mol
````````````````````````````````
             Mm = 40 g/mol
-FeO
Fe: 1 x 56 = 56 g/mol
 O: 1 x 16 = 16 g/mol
````````````````````````````
           Mm = 72 g/mol

-Fe2O3
Fe:  2 x 56 = 112 g/mol
 O. 3 x 16 = 48 g/mol
``````````````````````````````````
       Mm = 160 g/mol

-Mn2O7
Mn: 2 x 55 = 110 g/mol
   O:7 x 16 = 112 g/mol
``````````````````````````````````
           Mm = 222 g/mol
  

-Hg2O
Hg = 2 x  200.6 = 401.2 g/mol
  O = 1 x 16 = 16 g/mol
``````````````````````````````````````
             Mm = 417.2

-Al2O3
Al: 2 X 27 = 54 g/mol
  O: 3 x 16 = 48 g/mol
``````````````````````````````
           Mm = 102 g/mol

-V2O5
V: 2 x 51 = 102 g/mol
O: 5 x 16 = 80 g/mol
``````````````````````````````
           Mm = 182 g/mol

-MgO
Mg: 1 x 24 = 24 g/mol
  O: 1 X 16 = 16 g/mol
``````````````````````````````
           Mm = 40 g/mol

-CuO
Cu: 1 x 63.5 = 63.5 g/mol
  O: 1 x 16 = 16 g/mol
``````````````````````````````````
         Mm = 49.5 g/mol

-PtO2
Pt: 1 x 195 = 195 g/mol
  O: 2 x 16 = 32 g/mol
``````````````````````````````
           Mm = 227 g/mol

-CdO
Cd = 1 x 112.4 = 112.4 g/mol
  O= 1 x 16 = 16 g/mol
````````````````````````````````````````
               Mm = 128.4 g/mol