• Asignatura: Química
  • Autor: vanesamoran1
  • hace 9 años

Trióxido de di hierro. (Sol. 159,6 u)
C3H6 (Sol. 42 u)
Nitrato de potasio. (Sol. 101,1 u)
C2H6O (Sol. 46 u) Nesesito Esto Urgente Para Mañana Muchas Gracias

Respuestas

Respuesta dada por: snorye
1
Fe2O3

Fe = 2 X 55.84 = 111.68 g/mol
 O =  3 x 15.99 = 47.97 g/mol
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               Mm = 159.65 g/mol

C3H6
C =  3 x 12 = 36 g/mol
H = 6 x 1 = 6 g/mol
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              Mm = 42 g/mol

KNO3
K = 1 x 39.09 g/mol
N = 1 x 14 = 14 g/mol
O = 3 x 15.99 = 47.97 g/mo`l
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               Mm = 101.06 g/mol

C2H6O
C: 2 x 12 = 24 g/mol
H: 6 x 1 = 6 g/mol
O: 1 x 16 = 16 g/mol
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         Mm = 46 g/mol
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