Question

( + x³ + x²- 6) • ( x² + x + 1 )​

Answer 1

Explicación paso a paso:

$( {x}^{3} + {x}^{2} - 6) \times ( {x}^{2} + x + 1) \\ = {x}^{3} ( {x}^{2} + x + 1) + {x}^{2} ( {x}^{2} + x + 1) - 6( {x}^{2} + x + 1) \\ = {x}^{5} + {x}^{4} + {x}^{3} + {x}^{2} ( {x}^{2 } + x + 1) - 6( {x}^{2} + x + 1) \\ = {x}^{5} + {x}^{4} + {x}^{3} + {x}^{4} + {x}^{3} + {x}^{2} - ( {6x}^{2} + 6x + 6) \\ = {x}^{5} + {x}^{4} + {x}^{3} + {x}^{4} + {x}^{3} + {x}^{2} - {6x}^{2} - 6x - 6 \\ = {x}^{5} + ( {x}^{4} + {x}^{4} ) + ( {x}^{3} + {x}^{3} ) + ( {x}^{2} - {6x}^{2} ) - 6x - 6 \\ = {x}^{5} + {2x}^{4} + {2x}^{3} - {5x}^{2} - 6x - 6$