Question

ayuda a resolver esta ecuacion: 2x2-10=10x+5 con la fprmula general

Answer 1

$2x^2-10=10x+5$
$2x^2-10-\left(10x+5\right)=10x+5-\left(10x+5\right)$
$2x^2-10x-15=0$
$x=\frac{-\left(-10\right)+\sqrt{\left(-10\right)^2-4\cdot \:2\left(-15\right)}}{2\cdot \:2}=\frac{5+\sqrt{55}}{2}$
$x=\frac{-\left(-10\right)-\sqrt{\left(-10\right)^2-4\cdot \:2\left(-15\right)}}{2\cdot \:2}=\frac{5-\sqrt{55}}{2}$
$x=\frac{5+\sqrt{55}}{2},\:x=\frac{5-\sqrt{55}}{2}$