Question

5x+3y=12 4x+2y=5 elimicacion

Answer 1

5X + 3Y = 12 (1)

4X + 2Y = 5  (2)

 (1)x4:  20X + 12Y = 48

(2)x-5: -20X - 10Y = -25

   (1)x4:  20X + 12Y = 48

+(2)x-5:-20X  - 10Y = -25
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                           2Y = 23

2Y = 23

Y = 23/2

Reemplazo en (1)

5X + 3Y = 12

5X = 12 - 3Y

5X = 12 - 3(23/2)

5X = 12 - 69/2

5X = 24/2 - 69/2

5X = -45/2

X = -45/(5x2)

X = -9/2

Rta: X = -9/2; Y  = 23/2