Question

a) $\frac{3x}{2}- \frac{1}{2}= \frac{3x}{5} -\frac{1}{2}$
b) $\frac{x}{3}=\frac{1}{15} +\frac{2x}{5}$
c) $\frac{x+2}{3}-1=\frac{2x-1}{4}$


plis doy coronita x'd

Answer 1

Explicación paso a paso:

a)

$\frac{3x}{2} - \frac{1}{2} = \frac{3x}{5} - \frac{1}{2} \\ \frac{3x}{2} = \frac{3x}{5} \\ 15x = 6x \\ 15x - 6x = 0 \\ 9x = 0 \\ x = 0$

$\frac{x}{3} = \frac{1}{15} + \frac{2x}{5} \\ 5x = 1 + 6x \\ 5x - 6x = 1 \\ - x = 1 \\ x = - 1$

$\frac{x + 2}{3} - 1 = \frac{2x - 1}{4} \\ 4(x + 2) - 12 = 3(x - 1) \\ 4x + 8 - 12 = 6x - 3 \\ 4x - 4 = 6x - 3 \\ 4x - 6x = - 3 + 4 \\ - 2x = 1 \\ x = \frac{ - 1}{2}$