Question

Por favor lo necesito ahora y resueltos

Answer 1

Respuesta:

$(4x + 5) + (3x + 2) = \\ 4x + 5 + 3x + 2 = \\ (4x + 3x) +(5 + 2 ) = \\ 7x + 7$

$(5x - 5) + (4x - 7) = \\ 5x - 5 + 4x - 7 = \\ (5x + 4x) + ( - 5 - 7) = \\ 9x + ( - 12) = \\ 9x -1 2$

$(3w - 7) - (w - 1) = \\ 3w - 7 - w + 1 = \\ (3w - w) + ( - 7 + 1) = \\ 2w + ( - 6) = \\ 2w - 6$

$( {x}^{2} + 5x ) - ( {x}^{2} - 4x) = \\ {x}^{2} + 5x - {x}^{2} + 4x = \\ ( {x}^{2} - {x}^{2} ) + (5x + 4x) = \\ 9x$

$(2x + 3 {x}^{3} y) + (4x + 2 {x}^{2}y + {y}^{3} ) = \\ 2x + 3 {x}^{3} y + 4x + 2 {x}^{2} y + {y}^{3} = \\ (2x + 4x) + 3 {x}^{3} y + 2 {x}^{2} y + {y}^{3} = \\ 6x + 3 { x }^{3} y + 2 {x}^{2} y + {y}^{3}$

$(3 {x}^{2} + xy + {z}^{4} ) - ( - 3 {x}^{2} + 4xy - {z}^{4} ) = \\ 3 {x}^{2} + xy + {z}^{4} + 3 {x}^{2} - 4xy + { z}^{4} = \\ (3 {x}^{2} + 3 {x}^{2} ) + (xy - 4xy) + ( {z}^{4} + {z}^{4} ) = \\ 6 {x}^{2} + ( - 3xy) + 2 {z}^{4} = \\ 6 {x}^{2} - 3xy + 2 {z}^{4}$