Question

Se tiene 17/A= 19/B = 21/C y A + 2B + C=152 Halla: "A + B + C"​

Answer 1

☆ RESOLUCIÓN:

$\frac{17}{A} = \frac{19}{B} = \frac{21}{C} = k$

$→ \boxed{A = \frac{17}{k} }$

$→ \boxed{B = \frac{19}{k} }$

$→ \boxed{C = \frac{21}{k} }$

$⇒A + 2B + C = 152 \\ \frac{17}{k} + 2 \times \frac{19}{k} + \frac{21}{k} = 152 \\ \frac{17}{k} + \frac{38}{k} + \frac{21}{k} = 152 \\ \frac{17 + 38 + 21}{k} = 152 \\ \frac{76}{k} = 152 \\ \frac{76}{152} = k \\ \frac{1}{2} = k \\  \boxed{0.5 = k}$

$⇒A + B + C \\ \frac{17}{k} + \frac{19}{k} + \frac{21}{k} \\ \frac{17}{0.5} + \frac{19}{0.5} + \frac{21}{0.5} \\ \frac{17 + 19 + 21}{0.5} \\ \frac{57}{0.5} \\ \boxed{114}$

☆ RESPUESTA:

$\boxed{A + B + C = 144}$