Question

4x-3(x-3)=11
2y-2(6-x) =10​

Answer 1

Respuesta:

4x-3(x-3)=11

$4x-3x+9=11\\\\x+9=11\\\\x+9-9=11-9\\\\x=2$

2y-2(6-x) =10​

$-2\left(6-x\right)=10-2y\\\\\frac{-2\left(6-x\right)}{-2}=\frac{10}{-2}-\frac{2y}{-2}\\\\6-x=-5+y\\\\6-x-6=-5+y-6\\\\-x=y-11\\\\\frac{-x}{-1}=\frac{y}{-1}-\frac{11}{-1}\\\\x=-y+11$