Question

(x4 - 5x2 + 2) : (5x - 10)

(x3 + 2x2 - 5x + 2) : (2x + 3)

el que me pueda ayudar plis​

Answer 1

Respuesta:

Explicación paso a paso:

$\left(x^4\:-\:5x^2\:+\:2\right)\::\:\left(5x\:-\:10\right)\\\\\frac{x^3}{5}+\frac{2x^3-5x^2+2}{5x-10}\\\\\frac{x^3}{5}+\frac{2x^2}{5}+\frac{-x^2+2}{5x-10}\\\\\frac{x^3}{5}+\frac{2x^2}{5}-\frac{x}{5}+\frac{-2x+2}{5x-10}\\\\\frac{x^3}{5}+\frac{2x^2}{5}-\frac{x}{5}-\frac{2}{5}+\frac{-2}{5x-10}\\\\\frac{x^3}{5}+\frac{2x^2}{5}-\frac{x}{5}-\frac{2}{5}-\frac{2}{5x-10}$

$\left(x^3\:+\:2x^2\:-\:5x\:+\:2\right)\::\:\left(2x\:+\:3\right)\\\\\frac{\left(x^3+2x^2-5x+2\right)}{\left(2x+3\right)}\\\\\frac{x^2}{2}+\frac{\frac{x^2}{2}-5x+2}{2x+3}\\\\\frac{x^2}{2}+\frac{x}{4}+\frac{-\frac{23x}{4}+2}{2x+3}\\\\\frac{x^2}{2}+\frac{x}{4}-\frac{23}{8}+\frac{\frac{85}{8}}{2x+3}\\\\\frac{x^2}{2}+\frac{x}{4}-\frac{23}{8}+\frac{85}{8\left(2x+3\right)}$