Question

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$( \frac{7}{8} - \frac{7}{48} ) \times ( \frac{8}{9} + \frac{13}{21} )$
con procedimiento xfavor ​

Answer 1

Respuesta:

(7⁄8-7⁄48)x(8⁄9+13⁄21)

$\left(\frac{7}{8}-\frac{7}{48}\right)x\left(\frac{8}{9}+\frac{13}{21}\right)\\\\=\left(\frac{7}{8}-\frac{7}{48}\right)\left(\frac{8}{9}+\frac{13}{21}\right)x$

Answer 2

Respuesta:

$1\frac{43}{432}$

Explicación paso a paso:

$\left(\frac{7}{8}-\frac{7}{48}\right)\left(\frac{8}{9}+\frac{13}{21}\right)\\\\\frac{7}{8}-\frac{7}{48}\\\\=\frac{42}{48}-\frac{7}{48}\\\\=\frac{42-7}{48}\\\\42-7=35\\\\=\frac{35}{48}\\\\=\frac{35}{48}\left(\frac{8}{9}+\frac{13}{21}\right)\\\\\frac{8}{9}+\frac{13}{21}\\\\=\frac{56}{63}+\frac{39}{63}\\\\=\frac{56+39}{63}\\\\56+39=95\\\\=\frac{95}{63}\\\\=\frac{35}{48}\cdot \frac{95}{63}\\\\=\frac{35\cdot \:95}{48\cdot \:63}\\\\=\frac{7\cdot \:5\cdot \:95}{48\cdot \:63}$

$=\frac{7\cdot \:5\cdot \:95}{48\cdot \:7\cdot \:9}\\\\=\frac{5\cdot \:95}{48\cdot \:9}\\\\=\frac{475}{48\cdot \:9}\\\\48\cdot \:9=432\\\\=\frac{475}{432}\\\\\frac{475}{432}=1\frac{43}{432}\\\\=1\frac{43}{432}$