Question

(a+4)ca+3db+4 ; (b+2)c2a+1d2b+2 Calcular: para hoy xfa
al menos leanlo y respondan :)

Answer 1

Respuesta:

(a+4)ca+3db+4

$=ac\left(a+4\right)+3db+4\\=a^2c+4ac+3db+4$

(b+2)c2a+1d2b+2

$=2ca\left(b+2\right)+1\cdot \:2bd+2\\=2bca+4ca+1\cdot \:d\cdot \:2b+2\\=2bca+4ca+2bd+2$