Question

8-4×/3-2(5×+8)=2(4×+6)/9+2(10×+1) ​

Answer 1

Respuesta:

8-4×/3-2(5×+8)=2(4×+6)/9+2(10×+1) ​

$\left(8-4x\right)\left(20x+11\right)=\left(-10x-13\right)\times \:2\left(4x+6\right)\\-80x^2+116x+88=-80x^2-224x-156\\-80x^2+116x+88-88=-80x^2-224x-156-88\\-80x^2+116x-\left(-80x^2-224x\right)=-80x^2-224x-244-\left(-80x^2-224x\right)\\340x=-244\\\\\frac{340x}{340}=\frac{-244}{340}\\\\x=-\frac{61}{85}$