Question

$\frac{3b}{b {}^{2 } - 1 }{ -} \frac{2b}{b + 1 }$
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Answer 1

Respuesta:

$\boxed{\frac{3\text{b}}{\text{b}^2-1}-\frac{2\text{b}}{\text{b}+1}}$

Factorizar

$b^2-1=(b+1)(b-1)$

$\frac{3b}{\left(b+1\right)\left(b-1\right)}-\frac{2b}{b+1}$

$\frac{3b}{\left(b+1\right)\left(b-1\right)}-\frac{2b\left(b-1\right)}{\left(b+1\right)\left(b-1\right)}$

$\frac{3b-2b\left(b-1\right)}{\left(b+1\right)\left(b-1\right)}$

$3b-2b\left(b-1\right)=-2b^2+5b$

$-2b\left(b-1\right)=-2b^2+2b$

$3b-2b^2+2b=-2b^2+5b$

Solución

$\boxed{\frac{-2\text{b}^2+5\text{b}}{\left(\text{b}+1\right)\left(\text{b}-1\right)}}$

Saludos...