Question

Hallar la media diferencial de:
I. 40 y 32 III 56 86
II. 28 y 52 IV 27 y 19





AYUDA PORFA!! SOLO ME FALTA LA 3 Y LA 4 PORFA AYUDA ​

Answer 1

Respuesta:

 $\Huge\underline{\underline{\texttt{\Large\boldsymbol{Media \ Diferencial}}}}}}$

1. $\Large\boldsymbol{ a - b = b - d}$
2. $\Large\boldsymbol{ b + b = a + d}$
3. $\Large\boldsymbol{ 2b = a + d }$
4. $\Large\boldsymbol{ b =\dfrac{ (a + d)}{2} }$

Hallar la media diferencial de:

I. 40 y 32

$\Large\boldsymbol{ b =\dfrac{ (a + d)}{2} }$

$\Large\boldsymbol{ }b =\dfrac{ (40+ 32)}{2} }$

$\Large\boldsymbol{ }b =\dfrac{ 72}{2} }$

$\Large\boldsymbol{ }b =36 }$

II. 28 y 52

$\Large\boldsymbol{ }b =\dfrac{ (28+ 52)}{2} }$

$\Large\boldsymbol{ }b =\dfrac{ 80 }{2} }$

$\Large\boldsymbol{ }b =40}$

III 56 y 86

$\Large\boldsymbol{ }b =\dfrac{ (56+ 86)}{2} }$

$\Large\boldsymbol{ }b =\dfrac{ 142 }{2} }$

$\Large\boldsymbol{ }b =71 }$

IV 27 y 19

$\Large\boldsymbol{ }b =\dfrac{ (27+ 19)}{2} }$

$\Large\boldsymbol{ }b =\dfrac{ 46 }{2} }$

$\Large\boldsymbol{ }b =23 }$

Explicación paso a paso:https://brainly.lat/tarea/941019

Answer 2

Bien veamos

Hagamos cada uno

$40 - x = x - 32 \\ 40 + 32 = x + x \\ 72 = 2x \\ \\ \frac{72}{2} = \frac{2x}{2} \\ \mathbf{ \green{36 = x}}$

siguiente

$52 - x = x - 28 \\ 52 + 28 = x + x \\ 80 = 2x \\ \\ \frac{80}{2} = \frac{2x}{2} \\ \mathbf{ \green{40 = x}}$

$86 - x = x - 56\\ 86 + 56= x + x \\ 142 = 2x \\ \\ \frac{142}{2} = \frac{2x}{x} \\ \mathbf{ \green{71 = x}}$

sigamos

$27 - x = x - 19 \\ 27 + 19 = x + x \\ 46 = 2x \\ \\ \frac{46}{2} = \frac{2x}{2} \\ \mathbf{ \green{x = 23 }}$

espero haberte ayudado :3