Question

x² +'y²-4y -6y -12 =0​

Answer 1

Respuesta:

x=√−y2+10y+12 or x=−√−y2+10y+12

Explicación paso a paso:

Let's solve for x.

x2+y2−4y−6y−12=0

Step 1: Add -y^2 to both sides.

x2+y2−10y−12+−y2=0+−y2

x2−10y−12=−y2

Step 2: Add 10y to both sides.

x2−10y−12+10y=−y2+10y

x2−12=−y2+10y

Step 3: Add 12 to both sides.

x2−12+12=−y2+10y+12

x2=−y2+10y+12

Step 4: Take square root.

x=√−y2+10y+12 or x=−√−y2+10y+12