Question

AYUDAAAAA!!!!!
algebra

Answer 1

Ejercicio 3:

x+y= -z

hallar k = x³+y³+z³/xyz

________

(x+y+z)³ = 0

(x+y+z)³ = x³+y³+z³+3(x+y)(x+z)(y+z)

0³= x³+y³+z³+3(-z)(-y)(-x)

x³+y³+z³ -3xyz = 0

x³+y³+z³ = 3xyz

Remplazando

K = 3xyz/xyz = 3

Respuesta = K = 3