holi me ayudan plis porfa

Adjuntos:

Respuestas

Respuesta dada por: YHR5
1

PROBLEMA 1

N = tgϕ + ctgϕ \\ N =  \frac{6}{ \sqrt{ {10}^{2}  -  {6}^{2} } }  +  \frac{ \sqrt{ {10}^{2} -  {6}^{2}  } }{6} \\ N =  \frac{6}{8}  +  \frac{8}{6}  \\ N =  \frac{25}{12}

PROBLEMA 2

senϕ =   \frac{ \sqrt{ {15}^{2} -  {12}^{2}  } }{15}  =  \frac{9 }{15}  =  \frac{3}{5}  = 0.6

PROBLEMA 3

tg \alpha  + ctg \alpha  \\  \frac{3}{4}  +  \frac{4}{3}  \\  \frac{25}{12}

PROBLEMA 4

E = sen \alpha  + cos \alpha  \\ E =  \frac{1}{ \sqrt{ {1}^{2} +  {3}^{2}  } }  +  \frac{3}{ \sqrt{ {1}^{2} +  {3}^{2}  } }  \\ E =  \frac{1}{ \sqrt{10} }  +  \frac{3}{ \sqrt{10} }  \\ E =  \frac{4}{ \sqrt{10} }  \\ E =  \frac{4}{ \sqrt{10} }  \times  \frac{ \sqrt{10} }{ \sqrt{10} }  \\ E =  \frac{4 \sqrt{10} }{10}  \\ E =  \frac{2 \sqrt{10} }{5}

PROBLEMA 5

sec {}^{2}  \beta  + csc {}^{2}  \alpha  \\  (\frac{ \sqrt{ {8}^{2} {}^{2}  +  {4}^{2}  } }{4}) {}^{2}   +  (\frac{ \sqrt{ {4}^{2} +  {4}^{2}  } }{4}) {}^{2}   \\  (\frac{4 \sqrt{5} }{4}) {}^{2}   +  (\frac{4 \sqrt{2} }{4} ) {}^{2}  \\  ( \sqrt{5} ) {}^{2}  + ( \sqrt{2} ) {}^{2}  \\ 5 + 2 \\ 7

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