Question

(1-2y/3-y ) + y =1/y+2

Answer 1

Respuesta:

((1-2y)/3-y ) + y. = 1/y+2.

(3y-y^2)((1-2y)/3-y) + (3y-y^2)y = 3(3y-y^2)+2(3y-y^2)

y(1-2y)+3y^2-y^3 = 9y-3y^2+6y-2y^2

y-2y^2+3y^2-y^3 = 9y-3y^2+6y-2y^2

(1-9-6)y+3y^2-y^3 = -3y^2-2y^2

(-8-6)y+3y^2-y^3 = -5y^2

14y+3y^2-y^3 = -5y^2

14y+3y^2-y^3+5y^2 = -5y^2+5y^2

14y-y^3+5y^2 = 0

-1( 14y-y^3+5y^2 ) = -1(0)

-14y+y^3-5y^2 = 0

y^3-5y^2-14y = 0

y( y^2-5y-14 ) = 0

y( y^2-7y+2y-14 ) = 0

y ( y(y-7)+2(y-7)) = 0

y( (y+2)(y-7)) = 0

y(y+2)(y-7) = 0

y1 = 0 , y2 = -2 y y3 = 7

Explicación paso a paso: