Question

El valor numérico de 25+3(4^2-3^2)^2-5{62-5(3^2)} es​

Answer 1

Respuesta:

$25+3( {4}^{2} - {3}^{2})^{2} - 5(62 - 5( {3}^{2})$

$25 + 3(16 - 9)^{2} - 5(62 - 5(9)$

$25 + 3( {7}^{2}) - 5(62 - 45)$

$25 + 3(49) - 5(17)$

$25 + 147 - 85$

$172 - 85$

$87$

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