Question

[(+ 4) x (– 5) x (– 8)] ÷ [(– 4) x (+ 2)] =

[(– 8) x (– 2) x (+6) x (–2)] ÷ [(+ 4) x (+ 3)] =

[(+ 10) x (– 3) x (+ 8) x (+ 1)] ÷ [(– 15) x (+ 8)] =

Answer 1

Respuesta:

[(+ 4) x (– 5) x (– 8)] ÷ [(– 4) x (+ 2)] =

$\frac{\left(4\right)x\left(-5\right)x\left(-8\right)}{\left(-4\right)x\left(2\right)}\\\\=\frac{4x\cdot \:5x\cdot \:8}{-4x\cdot \:2}\\\\=\frac{160x^2}{-4\cdot \:2x}\\\\=-\frac{160x^2}{8x}\\\\=\frac{20x^2}{x}\\\\=-20x$

[(– 8) x (– 2) x (+6) x (–2)] ÷ [(+ 4) x (+ 3)] =

$=\frac{-8x\cdot \:2x\cdot \:6x\cdot \:2}{4x\cdot \:3}\\\\=\frac{-192x^3}{4\cdot \:3x}\\\\=\frac{-192x^3}{12x}\\\\=\frac{16x^3}{x}\\\\=-16x^2$

[(+ 10) x (– 3) x (+ 8) x (+ 1)] ÷ [(– 15) x (+ 8)] =

$=\frac{10x\left(-3\right)x\cdot \:8x\cdot \:1}{-15x\cdot \:8}\\\\=\frac{-10\cdot \:3\cdot \:8x^3}{-15x\cdot \:8}\\\\=\frac{-5\cdot \:2\cdot \:3\cdot \:8x^3}{-15x\cdot \:8}\\\\=\frac{2\cdot \:3\cdot \:8x^3}{3x\cdot \:8}\\\\=\frac{2\cdot \:8x^3}{x\cdot \:8}\\\\=\frac{2x^3}{x}\\\\=2x^2$